UGC NET PAPER 1 ICT MCQ
UGC NET paper 1 ICT MCQ
UGC NET/JRF 2020 Exam comprises of two papers – Paper 1 and Paper 2. “PAPER 1” is general paper for all stream students.Here we are providing you UGC NET/JRF paper 1 ICT “PREVIOUS YEAR” question WITH answer AND we also provide question with “explanation“.
1) Which Of The Following Is A Class-A IP Address?
A) 10010101.10101010.01010101.00001111
B) 11001101.10101110.01010101.01001111
C) 11010101.11101010.01010101.00101111
D) 01010101.10101010.01010101.00001111
Answer: D
Explanation: Class-A Range Is :0-127.Class-A First Bit Must Be 0.Here In Option “D” IP Address Starts With Bit 0.
IP Address | Range | First Octet Higher No |
Class A | 0 | 0-127 |
Class B | 10 | 128-191 |
Class C | 110 | 192-223 |
Class D | 111 | 224-239 |
Class E | 1111 | 240-255 |
2) The First Octet Higher Order Bit For Class-C IP Address Is?
A) 0 B)101 C)10 D)110
Answer: D
Explanation:
IP Address | Range | First Octet Higher No |
Class A | 0 | 0-127 |
Class B | 10 | 128-191 |
Class C | 110 | 192-223 |
Class D | 111 | 224-239 |
Class E | 1111 | 240-255 |
3)Which Of The Following Is A Class –D IP Address?
A) 11100101.10101010.01010101.00001111
B)11001101.11101110.01010101.01001101
C)10010101.11101010.01110101.00101011
D)01110101.10101010.0101.0101.00001111
Answer: A
Explanation:
IP Address | Range | First Octet Higher No |
Class A | 0 | 0-127 |
Class B | 10 | 128-191 |
Class C | 110 | 192-223 |
Class D | 111 | 224-239 |
Class E | 1111 | 240-255 |
4) Total Numbers Of Addressable Memory Blocks Using 10 Bits Address Line Is :-
A)1023 B)1024 C)2047 D)2048
Answer: B
Explanation: Here Bit Is Given 1o Bits So,210 =1024
5) The First Octet Higher Order But For Class –D IP Address Is :-
A)110 B)1111 C)1110 D)1010
Answer: C
Explanation:
IP Address | Range | First Octet Higher No |
Class A | 0 | 0-127 |
Class B | 10 | 128-191 |
Class C | 110 | 192-223 |
Class D | 111 | 224-239 |
Class E | 1111 | 240-255 |
6) There Are _________Bits In An Octet?
A)8 B)5 C)4 D)9
Answer:A
Explanation: 10011101.10111010.01010101.10001111
10011101=8 Bit .Here Each Octet Is Separated By “Dot” And Each Octet Has 8 Bit.
7) Which Class does 190.0.0.0 Belongs To?
A)Class-A B)Class-B C)Class- C D)Class-D
Answer:B
Explanation:
IP Address | Range | First Octet Higher No |
Class A | 0 | 0-127 |
Class B | 10 | 128-191 |
Class C | 110 | 192-223 |
Class D | 111 | 224-239 |
Class E | 1111 | 240-255 |
8) Which Of The Following In The Private IP Address ?
A)13.1.1.1 B)168.172.1.192 C)192.186.1.1 D)192.168.23.42
Answer: D
9) The Multicasting IP’s Are From Class –
a)Class-A b)Class-B c)Class-C d)Class D e)Class-E
Answer: d
Explanation: class-D is reserved for multicasting.
IP Address | Range | |
Class A | 0 | Leading Bit Pattern |
Class B | 10 | Leading Bit Pattern |
Class C | 110 | Leading Bit Pattern |
Class D | 111 | Reserved For Multicasting |
Class E | 1111 | Reserved For Experimental, Used For Research . . |
10) Which Range Of Addresses Can Be Used In The First Octet Of A Class C Address?
A)129-192 B)1-127 C)192-223 D)204-223
Answer: C
Explanation:
IP Address | Range | First Octet Higher No |
Class A | 0 | 0-127 |
Class B | 10 | 128-191 |
Class C | 110 | 192-223 |
Class D | 111 | 224-239 |
Class E | 1111 | 240-255 |
11 ) There Is ________Classes Of IP Address Version 4.
A)5 B)4 C)3 D)2 E)1
Answer:A
Explanation:
IP Address | Range | First Octet Higher No |
Class A | 0 | 0-127 |
Class B | 10 | 128-191 |
Class C | 110 | 192-223 |
Class D | 111 | 224-239 |
Class E | 1111 | 240-255 |
12) Which Of The Following Is The In Correct IP Address ?
A)213.231.56.4
B)253.251.256.0
C)176.9.59.4
D)188.40.139.40
Answer: B
Explanation: IP Address Range Must Be 0-255 We Can See Here In This Table Below.In Option B Range 256 Is Given Which Is Wrong.
IP Address | Range | First Octet Higher No |
Class A | 0 | 0-127 |
Class B | 10 | 128-191 |
Class C | 110 | 192-223 |
Class D | 111 | 224-239 |
Class E | 1111 | 240-255 |
13) The Private Class In Class-A Is ?
A)11.1.1.1 B)10.0.0.0 C)9.0.0.0 D)12.0.0.0
Answer: B
14) Which Of The Following Is A Class-B IP Address?
A) 10011101.10111010.01010101.10001111
B) 11011011.10101110.01010101.01001111
C) 11011101.11101010.01010101.01001111
D) 01010101.10101010.01011101.00001111
Answer: A
Explanation:
IP Address | Range | First Octet Higher No |
Class A | 0 | 0-127 |
Class B | 10 | 128-191 |
Class C | 110 | 192-223 |
Class D | 111 | 224-239 |
Class E | 1111 | 240-255 |
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