UGC NET PAPER 1 ICT MCQ

UGC NET paper 1 ICT MCQ

UGC NET/JRF 2020 Exam comprises of two papers – Paper 1 and Paper 2. “PAPER 1” is general paper for all stream students.Here we are providing you UGC NET/JRF paper 1 ICT PREVIOUS YEAR” question WITH answer AND we also provide question with “explanation“.

1) Which Of The Following Is A Class-A IP Address?

  A) 10010101.10101010.01010101.00001111

   B) 11001101.10101110.01010101.01001111

   C) 11010101.11101010.01010101.00101111

    D) 01010101.10101010.01010101.00001111

Answer: D

Explanation: Class-A Range Is :0-127.Class-A First Bit Must Be 0.Here In Option “D” IP Address Starts With Bit 0.

IP Address         Range  First Octet Higher No  
Class A    00-127
Class B10128-191
Class C110192-223  
Class D111224-239  
Class E1111240-255  

                  

2) The First Octet Higher Order Bit For Class-C IP Address Is?

  A) 0     B)101   C)10   D)110

Answer: D

Explanation:   

IP Address         Range  First Octet Higher No  
Class A    00-127
Class B10128-191
Class C110192-223  
Class D111224-239  
Class E1111240-255  

3)Which Of The Following Is A Class –D IP Address?

A) 11100101.10101010.01010101.00001111

B)11001101.11101110.01010101.01001101

C)10010101.11101010.01110101.00101011

D)01110101.10101010.0101.0101.00001111

Answer: A

Explanation:     

IP Address         Range  First Octet Higher No  
Class A    00-127
Class B10128-191
Class C110192-223  
Class D111224-239  
Class E1111240-255  

                  

       

4) Total Numbers Of Addressable Memory Blocks Using 10 Bits Address Line Is :-

A)1023  B)1024   C)2047   D)2048

Answer: B

Explanation: Here Bit Is Given 1o Bits So,210   =1024

5) The First Octet Higher Order But For Class –D IP Address Is :-

A)110  B)1111  C)1110   D)1010

Answer: C

Explanation:     

IP Address         Range  First Octet Higher No  
Class A    00-127
Class B10128-191
Class C110192-223  
Class D111224-239  
Class E1111240-255  

                 

6) There Are _________Bits In An Octet?

A)8       B)5      C)4     D)9

Answer:A

Explanation: 10011101.10111010.01010101.10001111

                      10011101=8 Bit .Here Each Octet Is Separated By “Dot” And Each Octet Has 8 Bit.  

7) Which Class does 190.0.0.0 Belongs To?

A)Class-A   B)Class-B      C)Class- C    D)Class-D

Answer:B

Explanation:     

IP Address         Range  First Octet Higher No  
Class A    00-127
Class B10128-191
Class C110192-223  
Class D111224-239  
Class E1111240-255  

             

8) Which Of The Following In The Private IP Address ?

A)13.1.1.1   B)168.172.1.192   C)192.186.1.1   D)192.168.23.42

Answer: D

9) The Multicasting IP’s Are From Class –

a)Class-A    b)Class-B  c)Class-C    d)Class D e)Class-E

Answer: d

 Explanation:     class-D is reserved for multicasting.

IP Address           Range   
Class A  0Leading Bit Pattern
Class B10Leading Bit Pattern
Class C110Leading Bit Pattern
Class D111Reserved For Multicasting
Class E1111Reserved For  Experimental, Used For  Research  .                                                                                                                                                                                                                                                                         .

       

10) Which Range Of Addresses Can Be Used In The First  Octet Of A Class C Address?

A)129-192   B)1-127   C)192-223  D)204-223

Answer: C

Explanation:    

IP Address         Range  First Octet Higher No  
Class A    00-127
Class B10128-191
Class C110192-223  
Class D111224-239  
Class E1111240-255  

11 ) There Is ________Classes Of IP Address Version 4.

A)5    B)4   C)3   D)2 E)1

Answer:A

Explanation:     

IP Address         Range  First Octet Higher No  
Class A    00-127
Class B10128-191
Class C110192-223  
Class D111224-239  
Class E1111240-255  

12) Which Of The Following Is The In Correct IP Address ?

A)213.231.56.4

B)253.251.256.0

C)176.9.59.4

D)188.40.139.40

Answer: B

Explanation:   IP Address Range Must Be 0-255 We Can See Here In This Table Below.In Option B Range 256 Is Given Which Is Wrong. 

    

IP Address         Range  First Octet Higher No  
Class A    00-127
Class B10128-191
Class C110192-223  
Class D111224-239  
Class E1111240-255  

13) The Private Class In Class-A Is ?

A)11.1.1.1   B)10.0.0.0   C)9.0.0.0    D)12.0.0.0

Answer: B

14) Which Of The Following Is A Class-B IP Address?

  A) 10011101.10111010.01010101.10001111

B) 11011011.10101110.01010101.01001111

C) 11011101.11101010.01010101.01001111

D) 01010101.10101010.01011101.00001111

Answer: A

Explanation:

IP Address         Range  First Octet Higher No  
Class A    00-127
Class B10128-191
Class C110192-223  
Class D111224-239  
Class E1111240-255  

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